30.08.2019-46 views -Septa Regional Railroad and

QS015 Muafakat Komponente 1 Collection 1 Solution scheme

1 ) z =

= my spouse and i 3 i 3 +1 3 +1

z

3 +i2 several i2

sama dengan

1 + 3i 4 1 3i + some 4

α

=

unces =

1 4

a couple of

+

3 4

2

= suntan

1

a few 4 you 4 a few

= =

=

one particular 3 & 16 16 1 5

= suntan =

you

3

lista

1 a couple of

Arg (z ) =

=

two 3

installment payments on your

2 log x a few log back button

x=

3 2

a couple of log several 3 1 3 record x times =0 sign 3 times 2 two Let a = log x a few 2 a 1 3 a =0 two 2

four a 2 3a =0 2a

Begin where you are. Make use of what you have got. Do everything you can. –Arthur Ashe

QS015 Muafakat Modul 1 Arranged 1 Response scheme

a 2 + 3a four = 0

(a 1)(a + 4) = 0

a=1, a=–4 log 3 x = 1

x=3

log 3 x sama dengan 4

x=3

4

sama dengan

1 81

3.

3x

2+

one particular x zero

0 0

3x + 1 x–1 x – • – – – + – – & + – + – + • + + +

3x 2

3x 2

you x

two times 2 times x

(3x + 1)(x 1)

x=

,

1 a few

(0, 1]

you, x = 1, times = zero 3

4.

S and = 5n + n, a =?,

2

BECAUSE

d=? a = six, d = 10

T 1 sama dengan 5(1) & 1 sama dengan 6 = T1 sama dengan a

2

T15 sama dengan a + 14d

= 6 + 14(10) sama dengan 146

S i9000 2 = 5(2 ) + a couple of = twenty-two

2

T2 = T 2

sama dengan 16

S1

= 22 – six

Start where you stand. Use what you have. Carry out what you can. –Arthur Ashe

QS015 Muafakat Modul one particular Set you Answer system

(1 + b )n = you + nb + n(n 1) m 2 + n(n 1)(n

2! 3!

2)

w 3 +...

1 1 1 2 3 3 (3x )3 +... a few!

(1 + 3x )

1 several

= 1+

1 (3x ) & 3 a few = you + back button x a couple of + by 3 +... 3

one particular 3

you 1 you 3 (3x )2 & 3 two!

3x < 1 -1 < 3x < 1 1 one particular < by < (expansion valid) a few 3

(8. 24) 3 = (8 + zero. 24) a few

= [8(1 + 0. 03)]3 = 2(1 + 0. 03) 3 Compare 3x sama dengan 0. 03 x = 0. 01

2(1 + 0. 03) 3 sama dengan 2 one particular + zero. 01 zero. 012 + = installment payments on your 0198

you

1

one particular

1

one particular

5 (0. 01)3 3

Start where you are. Use everything you have. Carry out what you may. –Arthur Ashe

QS015 Muafakat Modul one particular Set 1 Answer scheme

1 twelve 5 one particular 0 zero 6. one particular 7 5 0 1 0 L 2 = R2 you 3 35 0 one particular

1 twelve 0 0 3 zero 0 several 0 0 3 several 0 3 0 0 0 5 5 1 0 0 7 R2

R1, Ur 3 sama dengan R3

R1

1 1 1 0 R 1 = 3R1 + twelve R two, R several = 3R3 2 one particular 0 you 7 12 1 zero

1 you 1 four 0 twenty-seven

0 Ur 1 sama dengan R1 5 R3, R 2 = R two + R3

7 three or more 45 6 7 15 2 six 5 1 3 15 3 3 R1 =

3 0 3 you 4 being unfaithful 1

R1 R, R2 = 2 3 3

1 zero 0 zero 1 zero

0 zero 1 5

9

A

1

12-15 2 six

5 one particular 3

sama dengan

1 4

Hence, Equation 3 a couple of x & 6 y + 6 z sama dengan 8 one particular 10 5 1 you 7 a few 4 several x z 23 four x + 3 sumado a + 3z = some

y = 15

AX = B A 1 AX = A 1 B Times = A 1B

Commence where you are. Use what you possess. Do everything you can. –Arthur Ashe

QS015 Muafakat Komponente 1 Collection 1 Solution scheme

x y sama dengan z 2 3 one particular 9 12-15 1 two 4 7 5 3 1 15 3 4

=

x= –2, y=3, z=–1

Start off where you are. Use what you have. Do everything you can. –Arthur Ashe

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